The bricklayer exerted 150 newtons of force as he pushed the pushcart of bricks down

an alley that is 20 meters long. When the bricklayer reached the end of the alley, how

much work had he done?

3000 N

Step-by-step explanation:

The work done by a force on an object is given as the product of the force applied on the object and the distance moved by the object.

Mathematically:

W = F * d

The force applied by the man is 150 N and the distance moved is 20 m. Hence, the work done by the man is:

W = 150 * 20 = 3000 J

The work done by the man is 3000 Joules.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b