Hi can someone please help me with this question? thanks! :)

116°

Step-by-step explanation:

Based on the figure, it is a parallelogram. Also, lines QT and RS have the same length. So we can conclude that angles Q and R are congruent (as are angles T and S).

Solve for x:

Simplify parentheses:

Add 17 to both sides:

Subtract 4x from both sides:

Divide 5 from both sides:

Now that we know the value of x, insert it's value into the expressions:

Simplify parentheses:

Simplify:

The angles Q and R are 64°. Now that we know this, we can find the angle measure of T. The degree measure of a trapezoid add up to 360°, so add the angles of Q and R:

Subtract the total of two angles from 360°:

Divide 232° between the two remaining angles:

The angle measure of T is 116°.

Finito.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the line of