The population of a city (in millions) at time t (in years) is P(t)=2.6 e 0.005t , where t=0 is the year 2000. When will the population double from its size at t=0 ?

The population will double by the year 2139 from its value of 2.6 million in year 2000.

Population function :

Population size at t = 0

Population at t = 2.6 million.

For the population to double ;

2.6 × 2 = 5.2 million :

We solve for t

Take the In of both sides

The population will double after 139 years

Therefore, the population will double by the 2139 (Year 2000 + 139 years) = year 2139.

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  year 2139

Step-by-step explanation:

The population will double when the factor e^(.005t) is 2.

  e^(.005t) = 2

  .005t = ln(2)

  t = ln(2)/0.005 = 138.6

The population will be double its size at t=0 when t=138.6. That is the population will be about 5.2 million in the year 2139.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

i would you but i don't under stand the qustion

step-by-step explanation: