The volume of a gas is 550 mL at 960 mm Hg and 200.0 o C. What volume would the

pressure of the gas be 830 mm Hg if the temperature is reduced to 150.0 o C?

And replacing the info we have:

Step-by-step explanation:

For this case we wan assume that we have an ideal gas and we can use this relation:

And for this case we know:

Becuase

Because 1L = 1000 mL

And if we solve for V2 we got:

And replacing the info we have:

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).