The formula P = 4s gives the perimeter P of a square with side length s. How much greater is the perimeter of a square with a side length of 3 1/2 inches than a square with a side length of 3 inches?

1.16666666667  times bigger

Step-by-step explanation:

In this case i'm assuming, "Greater = bigger"

Formula for perimeter of square with given side length(s): P=4s

In order to find out how much greater the perimeter for one square vs. another, you must first evaluate the perimeter for both squares, then you must divide the perimeter of the bigger square over the smaller square (since the question is asking for how much bigger is the bigger square compared to the smaller square).

Thus,

Bigger perimeter square evaluation:

P=4(3.5)

P=14 units

Smaller perimeter square evaluation:

P=4(3)

P=12 units

Dividing the bigger square's perimeter over the smaller square's perimeter to find out how much times bigger the perimeter of the bigger square to the smaller square is:

14÷12≈1.16666666667

Therefore, the square with the side length of 3.5 is 1.16666666667  times bigger than the square with the side length of 3.

step-by-step explanation: