You randomly draw a marble from a bag of marbles that contains 3 blie marbles, 4 green marbles, and 5 red marbles. What is P?

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Question:

You randomly draw a marble from a bag of marbles that contains 3 blue marbles, 4 green marbles, and 5 red marbles. What is P?

a) selecting a blue marble

b) selecting a green marble

c) selecting a red marble

a) P(blue marble) = 1/4

b) P(green marble) = 1/3

c) P(red marble) = 5/12

Step-by-step explanation:

a) The probability of selecting a blue marble is given by,

P(blue marble) = no. of blue marbles/total no. of marbles

Where number of blue marbles = 3

Total number of marbles = 3 + 4 + 5 = 12

P(blue marble) = 3/12

P(blue marble) = 1/4

b) The probability of selecting a green marble is given by,

P(green marble) = no. of green marbles/total no. of marbles

Number of green marbles = 4

Total number of marbles = 12

P(green marble) = 4/12

P(green marble) = 1/3

c) The probability of selecting a red marble is given by,

P(red marble) = no. of red marbles/total no. of marbles

Where number of red marbles = 5

Total number of marbles = 12

P(red marble) = 5/12

So, the probabilities are

P(blue marble) = 1/4

P(green marble) = 1/3

P(red marble) = 5/12

chiken

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752