G A variable of a population has a mean mu equals 100 and a standard deviation sigma equals 21. a. The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with mean and standard deviation of

The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with mean of 100 and standard deviation of 3.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population

Mean 100, standard deviation 21.

The sampling distribution of the sample mean for samples of size 49

By the Central Limit Theorem

Mean 100

Standard deviation

The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with mean of 100 and standard deviation of 3.

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !