It took a skydiver 15 seconds to drop 450 feet. What is the
rate (in feet per/second) of the skydiver's drop?

30feet/second

Step-by-step explanation:

The rate in feet per seconds of the diver will be the speed of the diver.

Speed is the rate of change in distance of a body.

Speed = Distance/Time

Given distance or height of drop = 450feet

Time = 15seconds

Rate of change in distance = 450/15

Rate of change in distance = 30feet/second

The rate (in feet per/second) of the skydiver's drop is 30 feet/second

Step-by-step explanation:

To solve this problem let us itemized our given data

Given data

Distance of drop or height s =450 ft

Time taken to drop t = 15 sec

The rate of drop also speed/velocity v=?

We know that the

velocity v= distance travel/time

Substituting our data we have

v= 450/15=

v = 30 feet/second

your answer is 23/2 - 13.5

step-by-step explanation:

7/2 evaluates to

multiply x and 4.5

multiply x and 1

the x just gets copied along.

the answer is x

x

4.5*x evaluates to 4.5x

multiply 3 and 4.5x

multiply 1 and x

the x just gets copied along.

x

4.5*x*3 evaluates to 13.5x

7/2-4.5*x*3 evaluates to

  + 8 =

the answer is

7/2-4.5*x*3+8 evaluates to

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use mnemonics and other tricks.

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