Part A
A coin and a dice are tossed at the same time.
Select the list that shows all of the possible outcomes.
A. H, T, 1, 2, 3, 4, 5, 6
B. H, T
C. H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6
D. 1, 2, 3, 4, 5, 6
Part B
Find the probability of getting a head on the coin and a 6 In the dice.

Part A = C

Part B = 1/12

Step-by-step explanation:

Part A= this is because you need all the outcomes from the coin and from the dice joined together .

Part B= Because there is only one outcome that shows how you get a head on the coin and 6 on the dice.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

fourth month

step-by-step explanation:

it is the one with the most keychains.