Eric is preparing for a regional swim meet that is a month away. He swims the same distance and clocks his best time on several different days. He plots the best time (in minutes) he swam each day as his y-variable and the day he swam it as his x-variable. When he plots his times and finds a line of best fit, he gets the equation y=−0.03x+3.45.

If Eric continues to practice, on the 15th day his best time for the day should be _[blank]_ minutes.

Do not round your answer.

On the 15th day Eric's best time for the day should be 3.00 minutes.

Step-by-step explanation:

The line of best also known as the least square regression line is used to predict the value of the dependent variable based on a single independent variable.

The general form of a line of best is:

y = b X + a

Here,

y = dependent variable

x = independent variable

a = intercept

b = slope

In this case the dependent variable is defined as the best time (in minutes) Eric swam each day and the dependent variable is defined as the nth day.

The line of best fit is:

y = -0.03 x + 3.45

Compute the value of y for x = 15 as follows:

y = -0.03 x + 3.45

  = (-0.03 × 15) + 3.45

  = -0.45 + 3.45

  = 3.00

Thus, on the 15th day Eric's best time for the day should be 3.00 minutes.

answer: i believe the answer is e

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages