3 people traveled 27 miles total and person number 2 went 6 miles more than person number 1 and person number 3 went 3 miles more than person number 2. Solve problem algebraically

Answer : The distance travelled by person 1, person 2 and person 3 is, 4 miles, 10 miles and 13 miles respectively.

Step-by-step explanation :

Let the distance travelled by person number 1 = x miles

Then, the distance travelled by person number 2 = (x+6) miles

And, the distance travelled by person number 3 = (x+6) + 3 miles = (x+9) miles

Total distance travelled by 3 persons = 27 miles

As per question,

x + (x+6) + (x+9) = 27

3x + 15 = 27

3x = 27 - 15

3x = 12

x = 4

The distance travelled by person number 1 = x miles = 4 miles

The distance travelled by person number 2 = (x+6) miles = (4+6) miles = 10 miles

The distance travelled by person number 3 = (x+9) miles = (4+9) miles = 13 miles

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.