Taylor used 2 cans of blue paint and 5 cans of yellow paint to decorate a wall. Each can contains 200 millilitres of paint.

Which explanation correctly tells how to calculate how many more millilitres of yellow paint than blue paint were used?

A.
Step 1 Divide: 200 ÷ 5.
Step 2 Divide: 200 ÷ 2.
Step 3 Add the quotients.

B.
Step 1 Divide: 200 ÷ 5.
Step 2 Divide: 200 ÷ 2.
Step 3 Subtract the quotients.

C.
Step 1 Multiply: 200 × 5.
Step 2 Multiply: 200 × 2.
Step 3 Subtract the products.

D.
Step 1 Multiply: 200 × 5.
Step 2 Multiply: 200 × 2.
Step 3 Add the products.

Which value of m will create a system of parallel lines with no solution? y= mx - 6 8x - 4y = 12

In δabc shown below, ∠bac is congruent to ∠bca: triangle abc, where angles a and c are congruent given: base ∠bac and ∠acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: m∠bda and m∠bdc is 90° by the definition of a perpendicular bisector. ∠bda is congruent to ∠bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)

Consider the following equation. 1/2x^3+x-7=-3sqrtx-1 approximate the solution to the equation using three iterations of successive approximation. use the graph below as a starting point. a. b. c. d.