Supply rebuttals to the following complaints about the proof of Theorem 1.5.1.

(a) Every rational numbers has a decimal expansion so we could apply this same argument to show that the set of rational numbers between ° and 1 is uncountable. However, because we know that any subset of Q must be countable, the proof of Theorem 1.5.1 must be flawed.
(b) A few numbers have two different decimal representations. Specifically, any decimal expansion that terminates can also be written with repeating 9's. For instance, 1/2 can be written as .5 or as .4999 Doesn't this cause some problems?

mark other person brainliest

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61