Let X = the time between two successive arrivals at the drive-up window of a local bank. If X has an exponential distribution with λ = 1, (which is identical to a standard gamma distribution with α = 1), compute the following. (a) The expected time between two successive arrivals
(b) The standard deviation of the time between successive arrivals
(c) P(X ? 1)
(d) P(2 ? X ? 5)

a) E(X)=1

b) σ=1

c) P(X>1)=0.368

d) P(2<X<5)=0.128

Step-by-step explanation:

We have X: "the time between two successive arrivals at the drive-up window of a local bank", exponentially distributed with λ = 1.

a) We have to compute the expected time between two successive arrivals.

The expected value for X as it is exponentially distributed is:

b) We have to compute the standard deviation of X.

The standard deviation is calculated as:

c) The probability that X is larger than 1 (P(X>1))

We can express the probability as:

d) The probability that X is between 2 and 5 (P(2<X<5))

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation:

answer: i don't understand it

step-by-step explanation: sorry