A random sample of 100 people from region A and a random sample of 100 people from region B were surveyed about their grocery-shopping habits. From the region A sample, 16 percent of the people indicated that they shop for groceries online. From the region B sample, 24 percent of the people indicated that they shop for groceries online.

There is no significant difference between the two regions population proportion of people who go for online shopping

Step-by-step explanation:

We set the null hypothesis as H₀ : p₁ = p₂

Our alternative hypothesis is then Hₐ : p₁ ≠ p₂

Here we have the test statistic as follows;

Where:

p₁ = 16%

p ₂= 24%

n₁ = 100 people

n₂ = 100 people

q  = 1 - p

Therefore by plugging the values we get,

From the z relations the probability is found to be P(Z = -1.42) = 0.1573

Therefore, as p > α at 0.05, we fail to reject the null hypothesis, and therefore based on the statistical evidence, there is no significant difference between the two regions population proportion of people who go for online shopping

The proportion of population doing online shopping from both region aren't significantly different.

For region A:

For region B:  

The null Hypothesis

Alternative Hypothesis

The test statistic can be calculated as:

Putting values will give:

From the p values of Z score, the probability is calculated:

Thus, as the probability is bigger than the value of alpha at significance level 0.05, thus we can't reject null hypothesis.

The proportion of population doing online shopping from both region aren't significantly different.

Learn more about null and alternate hypothesis:

link

step-by-step explanation:

just plug in each number for x and see which ones work and don't