Mathematics, 06.05.2020 08:34 monsterwins292

A food service safety guideline is that the mercury in fish should be below 1 part per million. Listed below are the amounts of mercury found in tuna sampled at different stores in a major city. Construct a 98% confidence interval level estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi? 0.51 0.80 0.10 0.91 1.28 0.55 0.96

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Answer from: phillipfruge3

98% confidence interval level estimate of the mean amount of mercury in the population is [0.28 , 1.18].

Step-by-step explanation:

We are given that for the 69 second-year students in the study at the university, the sample mean procrastination score was 41.00 and the sample standard deviation was 6.89.

Firstly, the pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ t_n_-_1

where, $\bar X$ = sample mean amount = $\frac{\sum X}{n}$ = 0.73

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.381

n = sample size = 7

$\mu$ = population mean amount of mercury

Here for constructing 98% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.

So, 98% confidence interval for the population mean, $\mu$ is ;

P(-3.143 < t_6 < 3.143) = 0.98 {As the critical value of t at 6 degree

of freedom are -3.143 & 3.143 with P = 1%}

P(-3.143 < $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ < 3.143) = 0.98

P( $-3.143 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $3.143 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-3.143 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+3.143 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-3.143 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+3.143 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.73-3.143 \times {\frac{0.381}{\sqrt{7} } }$ , $0.73+3.143 \times {\frac{0.381}{\sqrt{7} } }$ ]

= [0.28 , 1.18]

Therefore, 98% confidence interval level estimate of the mean amount of mercury in the population is [0.28 , 1.18].

The interpretation of the above confidence interval is that we are 98% confident that the mean amount of mercury in the population will lie between 0.28 and 1.18.

Answer from: Quest

a) one student is chosen from classroom a, then a student is chosen from classroom b.

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b. this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes. this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes. this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes. this makes them dependent events.

Answer from: Quest

idk

step-by-step explanation: