When a coordinate grid is superimposed on a map of Harrisburg, the high school is located at (17, 21) and the town park is located at (28, 13).
If each unit represents 1 mile, how many miles apart are the high school and the town park?

13.6miles

Step-by-step explanation:

Using the formula for calculating the distance between two points

D = √(y2-y1)²+(x2-x1)²

When a coordinate grid is superimposed on a map of Harrisburg with the high school located at (17, 21) and the town park is located at (28, 13), our points are

P1 = (17,21)

P2 = (28,13)

x1 = 17, y1 = 21, x2 = 28, y2 = 13

Distance between the coordinates

D = √(28-17)²+(13-21)²

D = √11²+(-8)²

D = √121+64

D = √ 185

D = 13.6miles

The high school and the town park are 13.6miles apart

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places