What is the general form of the equation of a circle with center at(a, b) and radius of length m?

  x^2 +y^2 -2ax -2by +a^2 +b^2 -m^2 = 0

Step-by-step explanation:

The standard form equation is ...

  (x -a)^2 +(y -b)^2 = m^2

Subtracting the right side and simplifying gives the general form.

  x^2 +y^2 -2ax -2by +a^2 +b^2 -m^2 = 0

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2