Natasha had a $922.93 balance on her credit card at the beginning of September. Her credit card has an APR of 9.89%, compounded monthly, and a minimum monthly payment of 3.08% of the total balance. The following table shows Natasha’s credit card purchases over the next two months.
Month
Cost ($)
September
33.70
October
61.70
October
27.80
If Natasha makes only the minimum payments, what will her balance at the beginning of November? (Assume that the interest accrues before the monthly payment, and that the monthly payment occurs at the end of the month. Round all dollar values to the nearest cent.)
a.
$1,180.48
b.
$1,064.55
c.
$1,000.93
d.
$1,123.97

Natasha's opening balance = $922.93 APR = 9.89% compounded monthly Monthly interest = 9.89% / 12 = 0.0989 / 12 Interest for September = $922.93 x 0.0989 / 12 = $7.61 Balance on her card before September payment = $922.93 + $7.61 + $33.70 = $964.24 September payment = 3.08% of $964.24 = 0.0308 x $964.24 = $29.70 Balance on her card at the beginning of October = $964.24 - $29.70 = $934.54 Interest for October = $934.54 x 0.0989 / 12 = $7.70 Balance on her card before October payment = $934.54 + $7.70 + $61.70 + $27.80 = $1,031.74 October payment = 3.08% of $1,031.74 = 0.0308 x $1,031.74 = $31.78 Balance on her card at the beginning of November = $1,031.74 - $31.78 = $999.96

Step-by-step explanation:

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.