A School decides to organize field trips for all students. Tickets for first years were sold at GH¢0.40 per student and continuing students at GH¢0.20 per student. The total amount raised from the 500 tickets sold was GH¢ 160.00. You are to determine the number of first year students who bought the ticket as a percentage of the number of students who bought the ticket

60%

Step-by-step explanation:

You can solve this problem by setting up a system of equations.

Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:

0.4x+0.2y=160

x+y=500

Now, you can multiply the first equation by 5 on both sides to get:

2x+y=800

Subtracting the second equation from the first equation now yields:

x=300

y=200

Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse