0.105g of a given protein, containing unknown amounts of C H and O reacts with 02 to produce 0.257g of CO2 (44.01g/mol) and 0.035g of H2O (18.02g/mol), what is the empirical formula of the protein?

please explain

I just had this on an exam and had no clue how to do it, I need help

The answer to your question is C₃H₂O₁ or C₃H₂O

Step-by-step explanation:

Data

mass of protein = 0.105 g

elements = C, H, O

mass of CO₂ = 0.257 g

molar mass of CO₂ = 44.01 g/mol

mass of water = 0.035 g

molar mass of water = 18.02 g/mol

empirical formula = ?

Process

1.- Calculate the mass and moles of carbon

                    44 g of CO₂ 12 g of C

               0.257 g of CO₂ x

                                x = (0.257 x 12)/44

                                x = 3.084/44

                                x = 0.07 g of Carbon

                     12 g of C 1 mol

                     0.07 g of C  x

                                x = (0.07 x 1) / 12

                                x = 0.0058 moles of C

2.- Calculate the mass and moles of H

                      18 g of H₂O 2 g of H

                      0.035 g of H₂O x

                              x = (0.035 x 2) / 18

                             x = 0.0039 g of H₂

                         1 g of H 1 mol of H

                         0.0039 g of H   x

                              x = 0.0039 moles of H

3.- Calculate the mass and moles of O₂

mass of O₂ = 0.105g - 0.07 - 0.0039g

                   = 0.0311 g of O₂

                          16 g of O₂ 1 mol

                          0.0311 f of O₂  x

                             x = (0.0311 x 1)/16

                             x = 0.0019 moles of O₂

4.- Divide by the lowest number of moles

Carbon = 0.0058 / 0.0019 = 3.0

Hydrogen = 0.0039 / 0.0019 = 2.0

Oxigen = 0.0019 / 0.0019 = 1

5.- Write the empirical formula

                     C₃H₂O₁ or C₃H₂O

where are the options?

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.