Mathematics, 27.04.2020 01:36 ChHal1958

Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a
mean of 100 and a standard deviation of 15.
Click to view page 1 of the table. Click to view page 2 of the table
120
The area of the shaded region is
(Round to four decimal places as needed.)

Answers: 3

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Answer from: tiniecisneros28

The area of the shaded region which is the area to the left of the distribution curve is 0.9522

Given that :

Mean, μ = 100Standard deviation, σ = 15 Score, X = 125

We obtain the Zscore of the distribution :

Zscore = (X - μ) ÷ σZscore = (125 - 100) ÷ 15 = 1.667

The Area of the shaded region is the area to the left of the distribution :

P(Z < Zscore) = P(Z < 1.667)P(Z < 1.667) = 0.9522 (rounded to 4 decimal places)

Therefore, the area of the shaded region is 0.9522 which depicts the area to the left of the distribution.

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Answer from: cody1097

The area of the shaded region is 0.9082.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value, which is the area of the shaded region, is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 15, X = 120$

Area of the shaded region:

pvalue of Z

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{120 - 100}{15}$

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

The area of the shaded region is 0.9082.

Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those sc

Answer from: Quest

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

= $\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)$

side j'k'=distance between j' and k'

= $\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)$

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

Answer from: Quest

d. you cannot tell because there are no values shown.

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Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those sc...