When shooting two consecutive free throws during the regular season, a basketball player makes the first free throw 78% of the time. If he makes the first free throw, he makes the second one 88% of the time, but he only makes the second free throw 52% of the time after missing the first one. When he shoots a pair of free throws in the team’s first playoff game, what is the probability that he makes at least one free throw?

89.44%.

Step-by-step explanation:

Let's work out the probability he misses both throws:

Prob( he misses both throws) =  (1-0.78) * ( 1 - 0.52)

= 0.22*0.48

= 0.1056.

So the probability he makes at least one free throw = 1 - 0.1056

= 0.8944.

(It is 1 - 0.1056 because the default of missing  both throws is either  making one throw  on first or second attempt, or making both throws).

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

it would be:

c.parallelogram.