A. 4-sen α = cos^2 a

B. sen^2 α + cos a + 1=0

C. 5-5 cos α = 3 sen^2 α

D. 8 tg α = 3 cos α

E. 3 cot α = tan α

F. 2 tg α = 3+5 cot α

G. csc^2 = 3 cat α - 1

H. sen α = cos α

I. sen α + cos α = 1

J. 2 sen α = csc α

K. cos^2 α - sen^ 2 α = 1/2

i think the answer would be c

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3