Safia opens a new savings account with a 2.25% simple interest rate. She deposits $3,500 and earned $3,696.88 total (with interest) by the time she checks the account again. How long was the money left untouched in the savings account?

The money was left untouched for 2 years and 6 months or just 2.5 years

Step-by-step explanation:

In this question, we are asked to calculate the time taken for an amount deposited to earn a certain amount of interest.

Mathematically, simple interest can be calculated using the formula;

I = PRT/100

where I is the interest accrued which is 3696.88 - 3,500 = 196.88

P is the principal which is the amount deposited = 3,500 according to the question

R is the rate which is 2.25% according to the question

T is the time which we are to find

we can rearrange the formula making T the subject and we obtain the following;

T = 100I/PR

substituting the values listed above we have;

T = (100 * 196.88)/(3500 * 2.25)

T = 19688/7875

T = 2.5 years or 2 years 6 months

answer: c. is your answer

step-by-step explanation: get me a black leather coat

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt