A restaurant is offering a special deal on pizza and drinks. You can get 2 large pizzas and 4 large drinks for $16. Or, you can get 4 large pizzas and 7 large drinks for $30. How much would each pizza (p) and each drink (d) cost separately?

p=4 d=2

Step-by-step explanation:

To do this, we can set up a system of equations.

Special Deal 1:

2p+4d=16

Special Deal 2:

4p+7d=30

Now we can set this up for elimination, and try to eliminate the p variable.

Let's do this by multiplying the entire equation for Special Deal 1 by 2.

2(2p+4d=16)

4p+8d=32

Now we can eliminate p by subtracting the equation for special deal 2, by the equation for special deal 1.

4p+8d=32 minus

4p+7d=30 equals

d=2

Now we can plug that into the original equation to find the cost of p.

2p+4(2)=16

2p+8=16

Subtract 8 from both sides.

2p=8

p=4

Therefore, a pizza costs $4 and a drink costs $2.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

sine

step-by-step explanation: