Mathematics, 25.04.2020 19:17 copperrock15

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y

y = 3×10^8/x

What is the wavelength for radio waves with frequency 3 x 109?
A. 3×10^17m
B. 1×10-1m
C. 3×10-1m
D. 9×10^17

Answers: 3

Show answers

Answers

Answer from: marquezsturgis

The wavelength for radio waves with frequency 3 x 10⁹ is therefore; Choice (B); 1×10-¹m

The relationship between the wavelength in meters, x, and frequency, y is given by;y = 3×10⁸/x

According to the question;

We are required to determine the wavelength for radio waves with frequency 3 x 10⁹.

In essence; we are required to evaluate, x when the frequency, y is equal to 3 × 10⁹.

Therefore;

3 × 10⁹ = (3 × 10⁸)/x x = (3 × 10⁸)/(3 × 10⁹)x = 1 × 10-¹m.

Read more;

link

Answer from: angelteddy033

We have been given that the inverse variation $y=\frac{3\times 10^8}{x}$ shows the relationship between wavelength in meters, x, and frequency, y. We are asked to find the wavelength for radio waves with frequency $3\times 10^9$ .

To find the required wavelength, we substitute $y=3\times 10^9$ in our given equation and solve for x as:

$3\times 10^9=\frac{3\times 10^8}{x}$

$x=\frac{3\times 10^8}{3\times 10^9}$

We can see that both numerator and denominator has 3, so we can cancel it out.

$x=\frac{1\times 10^8}{1\times 10^9}$

Using quotient rule of exponents $\frac{a^m}{a^n}=a^{m-n}$ , we will get:

$x=1\times 10^{8-9}$

$x=1\times 10^{-1}$

Therefore, the wavelength for radio waves would be $1\times 10^{-1}$ meters and option B is the correct choice.

Answer from: Quest

a) one student is chosen from classroom a, then a student is chosen from classroom b.

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b. this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes. this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes. this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes. this makes them dependent events.

Answer from: Quest

step-by-step explanation: