Two skaters all racing toward the finish line of a race the first skater has for team lead and is traveling at a rate of 12 meters per second the second skater is traveling at a rate of 14 meters per second how long will it take for the second skater to past the first skater

t2 = 0.86 t1

0.286 seconds

Step-by-step explanation:

Given that the speed of the two skaters to be

S1 = 12 m/s

S2 = 14 m/s

Since it is a race, the distance covered will be the same. But of different time.

First Skater

Speed = distance/time

Let's assume that the distance covered when the second overtakes the first is d

12 = d/t1

d = 12t1

Since the time of both skaters are not given, let us assume that distance where the second skater overtakes the first is 4 metres. Therefore

t1 = 4/12 = 0.3333 second

Second skater

Speed = distance/ time

14 = 12t1/t2

t2 = 12t1/14

t2 = 0.86 t1

t2 = 0.86(0.333)

0.286 seconds

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."