Henrique drew and labeled the net shown. He also labeled the areas of the left and right triangular sides. A net has a rectangle at the center and 4 triangles on the sides. The rectangle has a length of 10 inches and height of 4 inches. 2 triangles have a base of 10 inches and a height of 5 inches. The other 2 triangles have an area of 13.6 inches squared. Use Henrique's work and finish finding the areas of the faces. What is the surface area of the rectangular pyramid?

Step-by-step explanation:

The net has a rectangle at the center. The area of the rectangle is expressed as

Area = length × width

Area of the rectangle = 10 × 4 = 40 inches²

The formula for determining the area of each triangular face is expressed as

Area = 1/2 × base × height

The area of each face of the triangle that has a base of 10 inches and a height of 5 inches is

Area = 1/2 × 10 × 5 = 25 inches²

The surface area of the rectangular pyramid is

Area of rectangle at the center + area of the four triangular faces

Therefore,

The surface area of the rectangular pyramid =

40 + 2(25) + 2(13.6) = 117.2 inches²

angles 1 and 3 are vertical angles, meaning that they are equal to each other. to solve this you may set angle 1 and 3 equal to each other and just solve for x like

110 = 2x + 10

100 = 2x

50 = x

check:

110 = 2* 50 + 10

110 = 100 + 10

110 = 110

hope this !

~just a girl in love with shawn mendes

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