We're given the equation

2x^2-x-5=0

Using the vietta formulas for S and P calculate the following

2 × X1^2 × X2 - 3X1 +1 + 2X1X2^2 - 3X2

where x1 and x2 the solutions of the equation above.

1

step-by-step explanation:

it's the only multiple of both and the least

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

y > 1/3x

y < = -x + 4

hope this : )

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step-by-step explanation: