Mathematics, 12.10.2019 07:50 maddie0533

L{sin^3 (at)}

so for i have this:
l{ sin(at) * [1/2 ( 1 - cos(2at)]}
1/2 l{sin(at)} - 1/2 l{cos(2at)sin(at)}
1/2 (a^2)/(s^2 + a^2) - 1/2 l{cos(2at)sin(at)}

how do i get rid of the cos(2at)sin(at) ?

Answers: 1

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L{sin^3 (at)}

so for i have this:
l{ sin(at) * [1/2 ( 1 - cos(2at)]}
1/2 l{...