Find the surface area of each figure pls 7-10

7) 42

8) 358

9) 320

10) 288

Step-by-step explanation:

Problems 7, 8, and 10 all use the same formula: the formula for the surface area of a rectangular prism.

Formula: 2 * (lw + lh + hw)

where l = length, w = width and h = height

This is a condensed form of the sum lw + lw + lh + lh + hw + hw where each product is a face of the prism.

replace each variable in the formula above with the values given in your problems for 7, 8 and 10:

7) 2 * (3*3 + 3*2 + 2*3) = 2 * (9 + 6 + 6) = 2 (21) = 42

8) 2 * (12*7 +12*5 + 5*7) = 2 * (84 + 60 + 35) = 2(179) = 358

10) 2* (12*4 + 12*6 + 4*6) = 2 * (48 + 72 + 24) = 2(144) = 288

Now 9 is a little different, as it contains a regular pentagon. However it is not much different from the other problems as it is also a prism.

The formula for the area of any regular polygon can be in the form:

Area = ap where the a stands for apothem (which is the distance from the center of a regular polygon to its side, in this case it is 5.5 yds) and the p is the perimeter of the polygon.

The reason for this formula involves the polygon being divided into as many congruent triangles as it has sides, but that is for another time : )

Given this formula for the area of the pentagon, you can substitute values:

Area = (5.5)(number of sides * length of a side)

Area =  (5.5)(5 * 8) = 110

And get that the area of the face is 110 yd^2

the rest of the faces are rather straightforward as they contain rectangles of sides 4 yds and 5 yds, and you would end up with 5 of them (for each side of the pentagon)

Therefore by adding up each of the bases and the sides, you should get:

110 + 110 + 20 + 20 + 20 + 20 + 20 = 320

Hope that helped : )

i am sorry it just submitted an answer but the answer is 365 boys. hopes this

step-by-step explanation:

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.