Which of the following statements is true? a) A 95% confidence interval is narrower than a 90% confidence interval for the same set of data. b) Increasing the sample size will decrease the margin of error in your confidence interval. c) The critical value is the variance of the sampling distribution. d) The point estimate is the measure of variation used in the computation of the margin of error. e) Smaller sample sizes produce larger margins of error because smaller samples always have larger standard deviations.

The correct option is;

b)

Step-by-step explanation:

a) 95% Sample CI =  152.6395 to  153.3605; Range = 0.721 Wider

90%  Sample CI = 152.6975 to  153.3025; Range= 0.605 Narrower

b) Sample size ∝ 1/Error²

Therefore, increasing the sample will decrease the margin of error

c) The critical value is the value of the test statistic at the level of confidence

Variance = (Standard deviation)²

d) Point estimate is the mean or average, variation is the range or also the variance

e) Smaller samples have their relative standard deviations which does not depend on the sample size

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)