A data set has a lower quartile of 3 and an interquartile range of 5. Which box plot could represent this data set? A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 2 to 15, and the box ranges from 3 to 8. A line divides the box at 6. A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 4 to 16, and the box ranges from 4 to 11. A line divides the box at 9. A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 2 to 15, and the box ranges from 3 to 10. A line divides the box at 8. A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 3 to 16, and the box ranges from 4 to 9. A line divides the box at 7.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

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step-by-step explanation:

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step-by-step explanation:

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step-by-step explanation: