URGENT HELP The diameter of the circle below is 5” and the length of the rectangle is twice its width. What is the area of the shaded part?

The shaded part is 17.875 in².

Step-by-step explanation:

To calculate the area of the shaded part,

Area of the circle

A = πr²

Find the radius (r), which is half the diameter.

r = d/2

r = 5/2

r = 2.5

Substitute the radius into the formula. I will round pi to 3.14.

A = πr²

A = (3.14)(2.5²)

A = 19.625

The area of the circle is 19.625 in².

Area of the triangle

A = (bh)/2

The base and height are the same as the diameter.

Substitute the base and the height.

A = (bh)/2

A = (5 x 5)/2

A = 25/2

A = 12.5

The area of the triangle is 12.5 in².

Area of the rectangle

A = lw

The length is double the diameter (l = 2d = 10) and the width is 5 (w = 5).

Substitute the length and the width.

A = lw

A = 10 x 5

A = 50

The area of the rectangle is 50 in².

Area of the shaded part

A = rectangle - white

A = rectangle - (circle + triangle)

Substitute the areas for the shapes.

A = rectangle - (circle + triangle)

A = 50 - (19.625 + 12.5)

A = 17.875

Remember the include the units:

17.875 in²

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