The angle measurements in the diagram are represented by the following expressions. \qquad \blueD{\angle A=8x -10^\circ}∠A=8x−10 ∘ start color #11accd, angle, A, equals, 8, x, minus, 10, degrees, end color #11accd \qquad \green{\angle B=3x + 90^\circ}∠B=3x+90 ∘ start color #28ae7b, angle, B, equals, 3, x, plus, 90, degrees, end color #28ae7b Solve for xxx and then find the measure of \greenD{\angle B}∠Bstart color #1fab54, angle, B, end color #1fab54: \greenD{\angle B} =∠B=start color #1fab54, angle, B, end color #1fab54, equals ^\circ ∘

answer: the answer is 23

step-by-step explanation:

0 is its x and y coordinate

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.