Find the length of a diagonal of a square with sides 10 inches long

quilt squares are cut on the diagonal to form triangular quilt pieces the hypotenuse of the resulting triangle is 10 inches long what is the side length of each piece?

-5

-5√2

-5√3

-10√2

•• Find the length of the missing sides in the triangle a triangle is not Drawn to scale.

by Jmjjosh02 02.03.2018

Report

ANSWER

Answers

jmjjosh02 is waiting for your help.

Add your answer and earn points.

carlosego

CarlosegoQuality Assurance

1) The problem says that the quilt squares are cut on the diagonal to form triangular quilt pieces. Then, the triangle pieces have angles of 45°, and the legs have the same lenght. So, you can solve the exercise by applying the Pythagorean Theorem:

h²:s²+s²

h²=2s²

h²/2=s²

s=√(h²/2)

"h" is the hypotenuse (h=10 inches) and "s" is the length of the sides.

When you substitute the value of the hypotenuse into the formula s=√(h²/2), you obtain the sides length:

s=√(h²/2)

s=√(10²/2)

s=5√2

What is the side length of each piece?  

The answer is: 5√2

2)Tan(α)=Opposite/Adjacent

α=30°

Opposite=17

Adjacent=x

When you substitute these values into Tan(α)=Opposite/Adjacent, you obtain:

Tan(α)=Opposite/Adjacent

Tan(30°)=17/x

x=17/Tan(30°)

x=17√3

Sin(α)=Opposite/Hypotenuse

α=30°

Opposite=17

Hypotenuse=y

Then, you have:

Sin(30°)=17/y

ySin(30°)=17

y=17/Sin(30°)

y=34

Step-by-step explanation:

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.