![\frac{3-[(4)(x-1)]}{x-1} =\frac{3-(4x-4)}{x-1} =\frac{3-4x+4}{x-1} =\frac{-4x+7}{x-1}](/tpl/images/0623/7486/0ea26.png)
leaving the fraction like:
I NEED HELP ITS URGENT PLEASE HELP ME
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Mathematics, 24.04.2020 08:00 minnie7760
I NEED HELP ITS URGENT PLEASE HELP ME
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