You toss a ball that travels on the path y= -0.1x^2 + 2x+4 where x and y are measured in meters. Sketch the path of the ball. How high does the ball go?

The ball goes 14 meters high

Step-by-step explanation:

Given the function

y= -0.1x^2 + 2x + 4

In the figure attached, the function is shown.

The maximum height is equivalent to the vertex of the function, which is obtained as follows:

Xv = -b/(2a) = -2/(2*-0.1) = 10

Yv = -0.1Xv^2 + 2Xv + 4

Yv = -0.1(10)^2 + 2(10) + 4 = 14

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars