Y^2– 14y + 48 = 0
Solve the following quadratic equations by completing the square.

We just started the introduction into circles and i have no idea how to do this.

Which statement is true about the local minimum of the graphed function? 27 +0,25) over the interval [-4, -2], the local minimum is 0. over the interval (-2,-1], the local minimum is 25. over the interval (-1, 4], the local minimum is 0. over the interval [4, 7), the local minimum is -7. (-34, 139,0n 760) in modo

X- 3 = 4 solve this algebraic expression