What is an equation of the line that is parallel to y = 5x - 7 and passes through (1, 11)
Enter your equation in the box

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

y = 5x - 7     The slope is 5, so the parallel line's slope is also 5.

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

y = 5x + b   To find b, plug in the point (1, 11) into the equation, the isolate/get the variable "b" by itself in the equation

11 = 5(1) + b    Subtract 5 on both sides to get "b" by itself

11 - 5 = 5 - 5 + b

6 = b

y = 5x + 6

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: