Find the equation of a line perpendicular to y=-2x+4 that contains the point (0,3).

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be perpendicular, their slopes have to be negative reciprocals of each other. (flip the sign +/- and the fraction(switch the numerator and the denominator))

For example:

Slope = 2 or

Perpendicular line's slope =   (flip the sign from + to -, and flip the fraction)

Slope =

Perpendicular line's slope =    (flip the sign from - to +, and flip the fraction)

y = -2x + 4   The slope is -2, so the perpendicular line's slope is

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

  Since they gave you the point (0, 3), which is the y-intercept, you can just plug 3 into "b". Another way to find b is plugging in the point on the line (0, 3) into the equation, then isolate/get the variable "b" by itself

3 = b

i think it would be 42cm

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.