What is the value of x in the following equation? 5x + 12 = 6(x + 1)
A. 6
B. 5 C. 24 D. 7

A: 6

Step-by-step explanation:

Our equation is 5x+12=6(x+1)

Our possible numbers are 6, 5, 24, or 7.

To figure this out you start putting the possible numbers in place of x so we'll start off using 6:

5*6+12=6(6+1).

5*6=30. 30+12=42. 6+1=7, 6*7=42.

This equals the same on both sides.

Next we'll go to 5:

5*5+12=6(5+1)

5*5=25, 25+12=37. 5+1=6, 6*6=36.

This doesn't equal the same amount on both sides.

Next is 24:

5*24+12=6(24+1)

5*24=120, 120+12=132. 24+1=25, 6*25=150

This doesn't equal the same amount.

Next is 7:

5*7+12=6(7+1)

5*7=35, 35+12=47. 7+1=8, 6*8=48.

This doesn't equal.

The only number that equals the same amount on both sides is A:6

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.