Mathematics, 23.04.2020 16:55 battlemarshmell
EXAMPLE 4 Find the sum of the series [infinity] (−1)n n! n = 0 correct to three decimal places. SOLUTION We first observe that the series is convergent by the Alternating Series Test because (i) 1 (n + 1)! = 1 n!(n + 1) 1 n! (ii) 0 < 1 n! ≤ 1 n → 0 so 1 n! → as n → [infinity]. To get a feel for how many terms we need to use in our approximation, let's write out the first few terms of the series: s = 1 0! − 1 1! + 1 2! − 1 3! + 1 4! − 1 5! + 1 6! − 1 7! + ⋯ = 1 − 1 + 1 2 − 1 6 + 1 24 − 1 120 + 1 − 1 5040 + ⋯ Notice that b7 = 1 5040 < 1 5000 = and s6 = 1 − 1 + 1 2 − 1 6 + 1 24 − 1 120 + 1 720 ≈ (rounded to six decimal places).
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Mathematics, 21.06.2019 17:00, joejoefofana
Simone claims the initial value and y-intercept are the same thing on a graph. is she correct? if you know that a line has a slope of and a y-intercept of 7, what is the equation for that line in slope-intercept form?
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Mathematics, 21.06.2019 18:00, BlueExorcistReaper
Solve 2^x=32 and rewrite this equation in a logarithmic form
Answers: 2
EXAMPLE 4 Find the sum of the series [infinity] (−1)n n! n = 0 correct to three decimal places. SOLU...
Social Studies, 16.11.2020 01:00