Hence solve the equation x^3+x^2-6x=0

x³ + x² - 6x = 0

x(x² + x - 6) = 0

x(x² + 3x - 2x - 6) = 0

x[x(x + 3) - 2(x + 3)] = 0

x(x - 2)(x + 3) = 0

x₁ = 0

x - 2 = 0 => x₂ = 2

x + 3 = 0 => x₃ = - 3

Step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2