The velocity function for a particle is v(t) = 2t - 5 ft/sec. Find the displacement for the particle from t = 0 to t = 4 sec. (Give answer with units)

The displacement is -4 ft.

Step-by-step explanation:

The velocity is:

v(t) = 2t - 5ft/s

If we want to find the displacement between t = 0s and t = 4s, we need to find the difference between the position at t = 0s and at t= 4s

The equation for the position is obtained by integrating over time:

P(t) = (2t^2)/2 - 5*t + c

where c is the initial position, then we have:

P(t) = t^2 - 5t

P(4) - P(0) = 4*4 - 5*4 - 0 = 16 - 20 = -4

The total displacement is -4 feet

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.