Solve the following systems of 3-variable linear equations.

x = 9/25

y = 7/25

z = 4/25

Step-by-step explanation:

2x + y = 1 (1)

3y + z = 1 (2)

x + 4z = 1 (3)

Elimination 1 and 2

2x + y = 1 | ×3 |

3y + z = 1 | ×1 |

6x + 3y = 3

3y + z = 1

--

6x - z = 2 (4)

Elimination 3 and 4

x + 4z = 1 | ×6 |

6x - z = 2 | ×1 |

6x + 24z = 6

6x - z = 2

--

25z = 4

z = 4/25

Elimination 3 and 4

x + 4z = 1 | ×1 |

6x - z = 2 | ×4 |

x + 4z = 1

24x - 4z = 8

+

25x = 9

x = 9/25

Subsitution 1

2x + y = 1

2(9/25) + y = 1

18/25 + y = 1

y = 1 - 18/25

y = 25/25 - 18/25

y = 7/25

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

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