Now it's time to tackle the original question.
Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to
point A, the cheetah traveled at an average rate of 40 mph
Can we say that this cheetah's average rate was 55 mph?
a. The average rate for the trip is equal to the total distance traveled divided by the total
time traveled. The following equations represent the distance traveled on each leg of the
trip

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

divide the numbers

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.