A long jumper leaves the ground at an angle of

22

°

above the horizontal, at a speed of

9

/

m

s

. The height of the jumper can be modeled by

=

h

x

+

−

0.046

x

2

0.362

x

, where

h

is the jumper's height in meters and

x

is the horizontal distance from the point of launch.

a) = 3.96

b) = 0.72

c) = 7.94

Step-by-step explanation:

Complete question.

(A long jumper leaves the ground at an angle of 20° above the horizontal, at a speed of 11 m/sec. The height of the jumper can be modeled by h(x) = -0.046x2+ 0.364x, where h is the jumper's height in meters and x is the horizontal distance from the point of launch. a. At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places. b. What is the maximum height of the long jumper? Round to 2 decimal places. c.What is the length of the jump? Round to 1 decimal place.)

Solution.

Data

Θ = 20

v = 11m/s

h(x) = -0.046x² + 0.364x

x = horizontal distance

h = height

a.

h(x) = -0.046x² + 0.364x

at maximum height,

d / dx (h) = 2(-0.46x) + 0.364

d / dx (h) = -0.092x + 0.364

at maximum height d / dx (h) = 0

0 = -0.092x + 0.364

0.092x = 0.364

x = 3.96.

b).

Hmax = -0.046x² + 0.364x

Hmax = -0.046(3.96) + 0.364(3.96)

Hmax = -0.72 + 1.44

Hmax = 0.72

c) the length of the jump can be calculated using the formula for range of a projectile

R = v² sin2Θ / g

g = 9.8m/s²

R = 11² * sin 2(20) / 9.8

R = 121 * sin40 / 9.8

R = 77.777 / 9.8

R = 7.936 = 7.94

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

care to share were the trapezoid shown is ?