A particle moves according to a law of motion s = f(t), 0 ≤ t ≤ 6, where t is measured in seconds and s in feet. f(t) = cos(πt/3) (a) Find the velocity at time t (in ft/s). v(t) = (b) What is the velocity after 2 s? (Round your answer to two decimal places.) v(2) = ft/s

(b)-0.91 ft/s

Step-by-step explanation:

Given the position function  s = f(t) where f(t) = cos(πt/3), 0 ≤ t ≤ 6

(a)The velocity at time t in ft/s is the derivative of the position vector.

(b)Velocity after 2 seconds

When t=2

The particle moves 0.91 ft/s in the opposite direction.

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